test: remove one more 64-bit multiplication

On some CPU cores, the compiler needs an helper to perform the 64-bit
multiplication. As the only remaining 64-bit multiplication in the code base
is not necessary, fix it rather than adding the helper.

Signed-off-by: Vincent Palatin <vpalatin@chromium.org>

BRANCH=none
BUG=none
TEST=build for Cortex-M0 platform.

Change-Id: I88dd7a4f2eabeca5b03fb3db232bbca9a037dcf8
Reviewed-on: https://chromium-review.googlesource.com/189151
Reviewed-by: Daisuke Nojiri <dnojiri@chromium.org>
Reviewed-by: Randall Spangler <rspangler@chromium.org>
Commit-Queue: Vincent Palatin <vpalatin@chromium.org>
Tested-by: Vincent Palatin <vpalatin@chromium.org>
This commit is contained in:
Vincent Palatin
2014-03-06 14:19:04 -08:00
committed by chrome-internal-fetch
parent cb462f29c6
commit ada635006d

View File

@@ -201,7 +201,7 @@ static int test_memset(void)
ccprintf(" %d us) ", t3.val-t2.val);
/* Expected about 4x speed gain. Use 3x because it fluctuates */
TEST_ASSERT((t1.val-t0.val) > (t3.val-t2.val) * 3);
TEST_ASSERT((t1.val-t0.val) > (unsigned)(t3.val-t2.val) * 3);
memset(buf, 128, len);
TEST_ASSERT_MEMSET(buf, (char)128, len);